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Saturday - 15 / 08 / 2026
Saturday - 08 / 15 / 2026

RC, RL and RLC passive filters: the complete guide

Dominate the RC, RL and RLC passive filters, learn how do they work, useful formulas and frequency response. Access!

What are passive filters?

They are circuits that allow signals from a determined frequency range and block signals outside this frequency range, they only have passive components (resistors, capacitor and/or inductors). In alternate current circuits, capacitors and inductors have impedance, which changes when frequency varies. To know more about impedance, click on the following link.

Resistance, Capacitance, Inductance, Impedance and ReactanceClick here

The formulas of capacitive and inductive reactances, respectively:

X_{c}=\frac{1}{2\pi f\cdot C}

X_{l}=2\pi f\cdot L

These formulas show that in a very high frequency, the capacitor behaves like short-circuit, while the coil behaves like an open circuit. For this reason, some input signals in determined frequencies are attenuated by the filters. The cutoff frequency depends on capacitance or inductance of capacitor and coil, respectively. Filters made with resistors and capacitors are called RC filters.

Low-pass RC

low-pass passive filters

It attenuates electric signals whose frequencies are higher than the cutoff frequency and allows the passage of lower frequencies.

High-pass RC

It does the inverse of low-pass filter, allows only the passage of signals whose frequency is higher than cutoff frequency. 

Demonstration of cutoff frequency equation for RC filters

First, considers voltage division equation.

  • For low-pass filters:

Vo=Vi(\frac{Zc}{Zc+R})

Since Zc=-jXc:

\frac{Vo}{Vi}=\frac{-jXc}{R-jXc}=\frac{Xc\angle-90}{\sqrt{(R^2+Xc^2)}\angle-tg^{-1}(Xc/R)}

On cutoff frequency f, Xc=R. Therefore, real part becomes:

Av=\frac{Vo}{Vi}=\frac{Xc}{\sqrt{R^2+Xc^2}}=\frac{R}{\sqrt{2R^2}}=\frac{1}{\sqrt{2}}=0,707

While the imaginary part:

\theta=-90^{\circ}+tg^{-1}1=-45^{\circ}

Considering Xc=R:

\frac{1}{2\pi f\cdot C}=R

\frac{1}{2\pi R\cdot C}=f

For high-pass RC filters, cutoff frequency formula is the same, but the phase angle \theta is 45º.

Bode diagram graphically represents the amplitude response in frequency’s function on the filter’s output. 0.707 is decibels is -3 dB. While the below graphic shows the filter’s phase shifting in frequency function. The point where amplitude is 0.707 and phase shifting is 45º marks the boundary between the band which pass through the filter and the blocked band. Source: wikimedia.
Bode diagram for a high-pass RC filter. Source: hetpro-store.com.

Passive filters with coils

It’s perfectly possible to build filters with coils, instead of capacitors, these are the RL filters. However, for low cutoff frequencies, the inductors needs high inductance, making them big and expensive.

On the left is a low-pass RL filter and on the right is high-pass.

Cutoff frequency and Bode diagram of RL filters

  • For low-pass RL filters.

Vo=Vi(\frac{R}{Z_{L}+R})

Considering Z_{L}=jX_{L}:

\frac{Vo}{Vi}=\frac{R}{R+jX_{L}}=\frac{R}{\sqrt{(R^{2}+X_{L}^{2})}\angle tg^{-1}(R/X_{L})}

On cutoff frequency, the gain Av is also 0.707 and phase angle \theta is -45º. While for high-pass RL filters, the phase angle is +45º. The cutoff frequency formula is:

R=2\pi fL

f=\frac{R}{2\pi L}

Pass-band and stop-band

It has two cutoff frequencies: lower and higher, to allow or block a signal from a band determined by the cutoff frequencies. Can be formed by a low-pass and a high-pass is series, a RLC circuit, which uses resistor, capacitor and inductor, or an algorithm who filtrates signals.

RLC passive filters can be parallel or series, to pass or block a frequency band. Source: Stack Exchange.

To calculate the lower cutoff frequency (f_{c1}) and the higher cutoff frequency (f_{c2}) of a RLC filter:

f_{c1}=f_{0}\left(\sqrt{1+\left(\frac{1}{2Q}\right)^{2}}-\frac{1}{2Q}\right)
 
f_{c2}=f_{0}\left(\sqrt{1+\left(\frac{1}{2Q}\right)^{2}}+\frac{1}{2Q}\right)
 
Where f_{0} is the resonance frequency and Q is the quality factor. Below are the equations to calculate both:
 
f_{0}=\frac{1}{2\pi \sqrt{LC}}
 
Q=\frac{f_{0}}{BW}
 
Where BW is band width, the frequency band allowed, or not, by the filter, the band width center is the resonance frequency.  
A Bode diagram example of a RLC band-pass filter. Image created by AI.
Bode diagram of a band-stop or notch filter. Source: pages.jh.edu.

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